Question

The count of a certain breed of bacteria was found to increase at the rate of 5% per hour. Find the bacteria at the end of 3 hours if the count was initially 600000.

Answer 1

Answer:

694575

Step-by-step explanation:

Initial Count = 6,00,000

Each hour the bacteria increases by : 5%

Total Bacteria after 1 hour : Initial bacteria x $\frac{105}{100}$

After 3 hours = 6,00,000 x $\frac{105}{100}$ x $\frac{105}{100}$ x $\frac{105}{100}$ = 0.6 x 105 x 105 x 105

= 6,94,575

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Answer 2

Given: The initial count of bacteria is$600000$, the bacteria increasing at the rate of $5$%, and the number of hours is$3.$

We have to find the count of bacteria at the end of $3$hours.

For which we are using the formula,

$\mathrm{A}=\mathrm{P}\left(1+\frac{R}{100}\right)^{n}$

Here we have,

$P=600000, R=5 andN=3$

Therefore,

$\mathrm{A}=\mathrm{P}\left(1+\frac{R}{100}\right)^{n}\\\\=>A=600000(1+\frac{5}{100} )^{3} \\=>694575$

The count of bacteria at the end of $3$hours is$694575$.