The count of bacteria in a certain experiment
was increasing at the rate of 5% per hour. Find
the count of bacteria at the end of 3 hours if
the count was initially 5,06,000.
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4
Answer:
We have, P
0
= Original count of bacteria =506000,
Rate of increase =R=2.5% per hour,
Time =2 hours
∴ Bacteria count after 2 hours = P
P=P
0
(1+
100
R
)
T
=506000×(1+
100
2.5
)
2
=506000×
100
102.5
×
100
102.5
=531616.25=531616 (approx)
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