Question

the count of bacteria is increased at the rate of 2.5% per hour. Find the count of bacteria at the end of 2 hours if it was 5,06,000 in the beginning.

Answer 1

5,31,300 bacterias are in end of 2 hours

Answer 2

Using the formula for compound interest,
$p(1 + r \div 100 ){}^{t}$
Here t=2.
p=5,06,000.
r=2.5.

We get
Ans= 50.6x102.5x102.5=531616.25=531616(no fraction)

Please overlook calculation mistakes if any