The count rate of a radioactive source at t=0 was 1600 counts/as and at t=8s, it was 100 counts/as. The count rate (in counts) at t = 6s will be
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Solution :-
Step - (I)
A = A0 ( 1/2) ^t/T
100 = 1600 ( 1/2) ^t/T
=> T = 2 second
Step -(ii)
At t = 6 second
A' = 1600 ( 1/2) ^6/2
=> 200 count per second
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@bebrainly
Step - (I)
A = A0 ( 1/2) ^t/T
100 = 1600 ( 1/2) ^t/T
=> T = 2 second
Step -(ii)
At t = 6 second
A' = 1600 ( 1/2) ^6/2
=> 200 count per second
==============
@bebrainly
Answered by
0
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