Physics, asked by kapil8816, 1 year ago

The count rate of a radioactive source at t=0 was 1600 counts/as and at t=8s, it was 100 counts/as. The count rate (in counts) at t = 6s will be

Answers

Answered by kirtisingh01
29
Solution :-

Step - (I)

A = A0 ( 1/2) ^t/T

100 = 1600 ( 1/2) ^t/T

=> T = 2 second

Step -(ii)

At t = 6 second

A' = 1600 ( 1/2) ^6/2

=> 200 count per second

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@bebrainly
Answered by hritik633
0

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