Question

The crank radius of a single-cylinder I. C. engine is 60mm and the diameter of the cylinder is 80mm. The swept volume of the cylinder in cm is (A) 48 (B) 96 (C) 302 (D) 603

Answer 1

Option C is the answer.

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Answer 2

Answer:

The swept volume of the cylinder is given by option D

Explanation:

The swept volume of the cylinder is given by:

$V_{s}=\frac{\pi}{4} \times D^{2} \times L$

where $D=$ diameter of cylinder and $L=$ length of stroke

Length of the stroke is given by:

$L=2 r$

where $r=$ crank radius

Given:

$r=60 \mathrm{~mm}, D=80 \mathrm{~mm}$

To find:

Swept volume

Calculation:

Length of the stroke $(L)$ is:

$L=2 r=2 \times 60=120 \mathrm{~mm}$

Swept volume is $V_{s}=\frac{\pi}{4} \times D^{2} \times L\\\\=\frac{\pi}{4} \times 80^{2} \times 120\\=603185.78 \mathrm{~mm}^{3}\\=603.185\mathrm{~cm}^{3}$