Question

The cricket ball has a mass of 0.16 kg and it hits the bat with a speed of 25 m/s. After being
in contact with the bat for 0.0013 s, the ball rebounds with a speed of 22 m/s in the direction
exactly opposite to its original direction.
(a) State the difference between speed and velocity.
(b) Calculate
(i) the change in velocity of the cricket ball,
velocity change
(ii) the average acceleration of the ball whilst it is in contact with the bat,
acceleration​

Answer 1

Answer:

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Answer 2

Answer:

Velocity change = -3 m/s and acceleration =$-2307.69 m/s^2$

Explanation:

Mass of the cricket ball =0.16kg

initial speed (u) of the ball =25 m/s

final speed of ball (v)=22 m/s

Time of contact with the ball= 0.0013s

• Speed is a scalar quantity and defined as $speed=\frac{distance}{time}$

      velocity is vector quantity and defined as $velocity = \frac{displacement}{time}$

• The change in velocity of the cricket ball = v - u= -3m/s
• Average acceleration of the ball in contact with the bat = $a=\frac{v-u}{t}=\frac{-3}{0.0013}=-2307.69 m/s^2$