Physics, asked by jobaer593, 9 months ago

The critical angle for certain wave length of light in case of a piece of glass is 30o and the amplitude of the light is 5cm. Calculate i. The polarization angle of glass ; ii. The angle of refraction ; iii. The refractive index of the medium ; iv. Initial intensity of the light ; and v. Final intensity of the light.

Answers

Answered by kbsingha1212
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Answer:

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Answered by Anonymous
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Answer:

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Explanation:

When light encounters a boundary between two media with different refractive indices, some of it is usually reflected as shown in the figure above. The fraction that is reflected is described by the Fresnel equations, and is dependent upon the incoming light's polarization and angle of incidence.

The Fresnel equations predict that light with the p polarization (electric field polarized in the same plane as the incident ray and the surface normal at the point of incidence) will not be reflected if the angle of incidence is

{\displaystyle \theta _{\mathrm {B} }=\arctan \!\left({\frac {n_{2}}{n_{1}}}\right)\!,}\theta _{{\mathrm  {B}}}=\arctan \!\left({\frac  {n_{2}}{n_{1}}}\right)\!,

where n1 is the refractive index of the initial medium through which the light propagates (the "incident medium"), and n2 is the index of the other medium. This equation is known as Brewster's law, and the angle defined by it is Brewster's angle.

The physical mechanism for this can be qualitatively understood from the manner in which electric dipoles in the media respond to p-polarized light. One can imagine that light incident on the surface is absorbed, and then re-radiated by oscillating electric dipoles at the interface between the two media. The polarization of freely propagating light is always perpendicular to the direction in which the light is travelling. The dipoles that produce the transmitted (refracted) light oscillate in the polarization direction of that light. These same oscillating dipoles also generate the reflected light. However, dipoles do not radiate any energy in the direction of the dipole moment. If the refracted light is p-polarized and propagates exactly perpendicular to the direction in which the light is predicted to be specularly reflected, the dipoles point along the specular reflection direction and therefore no light can be reflected. (See diagram, above)

With simple geometry this condition can be expressed as

{\displaystyle \theta _{1}+\theta _{2}=90^{\circ },}\theta _{1}+\theta _{2}=90^{\circ },

where θ1 is the angle of reflection (or incidence) and θ2 is the angle of refraction.

Using Snell's law,

{\displaystyle n_{1}\sin \theta _{1}=n_{2}\sin \theta _{2},}n_{1}\sin \theta _{1}=n_{2}\sin \theta _{2},

one can calculate the incident angle θ1 = θB at which no light is reflected:

{\displaystyle n_{1}\sin \theta _{\mathrm {B} }=n_{2}\sin(90^{\circ }-\theta _{\mathrm {B} })=n_{2}\cos \theta _{\mathrm {B} }.}n_{1}\sin \theta _{{\mathrm  {B}}}=n_{2}\sin(90^{\circ }-\theta _{{\mathrm  {B}}})=n_{2}\cos \theta _{{\mathrm  {B}}}.

Solving for θB gives

{\displaystyle \theta _{\mathrm {B} }=\arctan \!\left({\frac {n_{2}}{n_{1}}}\right)\!.}\theta _{\mathrm {B} }=\arctan \!\left({\frac {n_{2}}{n_{1}}}\right)\!.

For a glass medium (n2 ≈ 1.5) in air (n1 ≈ 1), Brewster's angle for visible light is approximately 56°, while for an air-water interface (n2 ≈ 1.33), it is approximately 53°. Since the refractive index for a given medium changes depending on the wavelength of light, Brewster's angle will also vary with wavelength.

The phenomenon of light being polarized by reflection from a surface at a particular angle was first observed by Étienne-Louis Malus in 1808.[3] He attempted to relate the polarizing angle to the refractive index of the material, but was frustrated by the inconsistent quality of glasses available at that time. In 1815, Brewster experimented with higher-quality materials and showed that this angle was a function of the refractive index, defining Brewster's law.

Brewster's angle is often referred to as the "polarizing angle", because light that reflects from a surface at this angle is entirely polarized perpendicular to the plane of incidence ("s-polarized"). A glass plate or a stack of plates placed at Brewster's angle in a light beam can, thus, be used as a polarizer. The concept of a polarizing angle can be extended to the concept of a Brewster wavenumber to cover planar interfaces between two linear bianisotropic materials. In the case of reflection at Brewster's angle, the reflected and refracted rays are mutually perpendicular.

For magnetic materials, Brewster's angle can exist for only one of the incident wave polarizations, as determined by the relative strengths of the dielectric permittivity and magnetic permeability.[4] This has implications for the existence of generalized Brewster angles for dielectric metasurfaces.[5]

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