Question

The critical angle for light wave going from a medium in which wavelenght is 4000A° to a medium in which its wavelenght is 6000A°, is

Answer 1

Answer:

Explanation:

we know that

(v1/v2)=(w1/w2)=(u2/u1)

v=velocity in medium

w=wavelength

u =refractive index

u2/u1 = 6000/4000 = 3/2

u1/u2 = 2/3    

u2sin C=u1sin90    Cis critical angle

sinC=u1/u2

C=sin^-1(2/3)  

Answer 2

Answer:

*An object sinks in water if its density is greater than that of water.* An object floats in water if its density is less than that of water.