the critical angle for turpentine with respect to air is 43 degree. find its refractive index
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Answer:
Sin 43 =0.83
Explanation:
Because the sin of critical angle is refractive index cause due to Snell's law
sin i /sin r = refractive index
in condition of critical angle then sin r is 1 cause the angle of refraction is 90 so sin 90 is 1 therefore the sin i equals refractive index then i is critical angle.
the critical angle given is 43 degree so
sin 43 is 0.83
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