Question

the critical angle for water is 48.2 degrees,then its refractive index is​

Answer 1

Answer:

Step-by-step explanation:

Our aim is, knowing that the critical angle for water is 48.2 degrees, to find its refractive index.

The first thing we should do is to remind the idea of critical angle. What is a critical angle? - A critical angle is an angle made by a ligt that incises in two different denser surfaces, one with a less dense medium and other with a normal denser medium for example. This light is no longer refracted but reflected..

Hence lets consider n = 1 the refractive index of air, and y = 48.2.

We know that x = 90º because we have a critical angle, in which the angle refracts.

sin (x) = sin (90º) = 1, thus m*sin(y) = n*sin(x), hence m = 1 / sin(48.2) is our refractive index.

m = 1.341424808

Hence, its refractive index is 1.341424808.

Answer 2

Answer:

the answer is q

1.34

Step-by-step explanation:

use

m sin i=m sin r