Question

the critical angle of a interface medium A and air is 45 then the refractive index of A is

Answer 1

refractive index = 1/sin C
=1/sin 45
=1/1/√2
=√2=1.414

Answer 2

Explanation:

${\huge\fbox\pink{A}\fbox\blue{N}\fbox\purple{S}\fbox\green{W}\fbox\red{E}\fbox\orange{R}}$

The refractive index of prism when the critical angle is 45° is 1.414.