Question

the critical angle of a medium 30 degree then its refractive index is​

Answer 1

Explanation:

The angle is said to be a critical angle , when the ratio between angle of incidence and angle of refraction is 90°. Therefore the refractive index of the liquid is 2 when their critical angle is 30°.

Answer 2

Answer:

Here's your answer mate :

Explanation:

What is the refractive index if the critical angle is 30?

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You have not given enough information to say for sure. The critical angle depends on the refractive index on both sides of the interface. The equation for the critical angle is

θc=sin−1(n2n1)

Since you have only specified the angle θc=30∘ , the only thing you can do is solve for n2/n1 .

n2n1=sin(θc)=sin(30∘)=0.5

Now, if I assume that the second medium is air so n2 = 1.0, we can get a value for n1 .

n1=n20.5=1.00.5=2.0

Rule the new normal!

Critical angle :

The critical angle is the angle of incidence where the angle of refraction is 90∘

The light must travel from an optically more dense medium to an optically less dense medium.

The critical angle s related to the refractive index as

θc=sin−1(n2/n1)

rearranging

n2/n1 = sin(θc)

given θc= 30∘

by substituting the values

n2/n1 =sin(30∘) = o.5

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