The critical angle of a medium with respect to vacuum is 30 degree . The velocity of light in the medium is a) 3x10power8m/s b)2x108m/s c) 1.5x108m/s d)3.1x108m/s give short explanation
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It's 1.5*10^8 m/s
See the formula is
Refractive index= cosec of the critical angle
So , we get , refractive index as 2 bcs sin30 is 1/2
So , refractive index=velocity of light in air/ velocity of medium
Therefore , we get the answer as 1.5 m/s
As
2=(3*10^8)/ x
Where. X is speed of light in medium
2X=3*10^8
X=3*10^8/2
See the formula is
Refractive index= cosec of the critical angle
So , we get , refractive index as 2 bcs sin30 is 1/2
So , refractive index=velocity of light in air/ velocity of medium
Therefore , we get the answer as 1.5 m/s
As
2=(3*10^8)/ x
Where. X is speed of light in medium
2X=3*10^8
X=3*10^8/2
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