Question

The critical angle of kerosene is 45 degrees Calculate its refractive index

Answer 1

Answer:

Determine refractive index of a

Substance if critical angle is 45⁰,

Solution: Here, C=45⁰,=?

=1sinC=1 sin45⁰=11/2=2.

Answer 2

Given:

The critical angle of kerosene is 45°.

To find:

Kerosene's refractive index.

Solution:

We know that the refractive index of the material is given by the formula,

$n=\frac{1}{sinC}$                                              ...(I)

Where,

• n is the refractive index
• C is critical angle

Here, it is given that, the critical angle of the kerosene is 45°.

From (I),

   $n=\frac{1}{sinC}$

⇒$n=\frac{1}{sin(45)}$

⇒$n=\frac{1}{\frac{1}{\sqrt{2} }}$

⇒$n=\sqrt{2}$

⇒$n=1.41421356$

Hence, the refractive index of kerosene is 1.41421356.

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