Question

The critical angle of kerosene is45.calculate its refractive index

Answer 1

$\Large\underline{\underline{\sf Given:}}$

• Critical angle $\sf{\theta_c}$=45°

$\Large\underline{\underline{\sf To\:Find:}}$

• Refractive Index $\sf{(\mu)}$=?

$\Large\underline{\underline{\sf Formula\:Used:}}$

$\large{\boxed{\boxed{\sf \pink{\mu=\dfrac{1}{sin\theta_c}}}}}$

$\Large\underline{\underline{\sf Solution:}}$

$\implies{\sf \mu=\dfrac{1}{sin45° }}$

$\implies{\sf \mu=\sqrt{2} }$

$\implies{\sf \mu=0.303}$

$\Large\underline{\underline{\sf Answer:}}$

⛬ Refractive index of kerosine is 0.303