Question

The critical constants for water are 374°C, 218 atm and 0.0566 L mot
(2) van der Waal constant
() van der Waal constant a 0.189 L mot
in der Waal constant b-00189 L moi
3
(3) van der Waal constant b = 2.095 L mot
(4) At critical point z=​

Answer 1

Welcome Student,

◆ Answer -

a = 2.095 L².atm/mol²

b = 0.0189 L/mol

R = 0.0585 L.atm/molK

● Explaination -

# Given -

T = 374 ℃ = 647 K

P = 218 atm

V = 0.0566 L/mol

# Solution -

Standard form of van der Waal's equation is given by -

P = RT/(V-b) - a/V²

Van der Waal's constant 'a' is calculated as -

a = 3PV²

a = 3 × 218 × 0.0566²

a = 2.095 L².atm/mol²

Van der Waal's constant 'b' is calculated as -

b = V/3

b = 0.0566/3

b = 0.0189 L/mol

Value of R is calculated by -

R = 8PV / 3T

R = (8 × 218 × 0.0566) / (3 × 647)

R = 0.0585 L.atm/molK

Thanks dear...