Physics, asked by ppatel972383, 8 months ago

The critical temperature of Nb is 9.15 K. At zero kelvin the critical field is
0.196 tesla. Calculate the critical field at 6K.

Answers

Answered by mad210216
11

The critical field at 6k is 0.011 Telsa.

Explanation: The critical field at 6k , we have the formula for critical field

  •            Hc(T) = Hc(0)[ 1 - (T/Tc)²]

Here given Critical field at zero Temperature Hc(0) = 0.0196,    Critical temperature Tc = 9.15k, and find critical field at T = 6K

Therefore

  •                    Hc(T) = Hc(0)[ 1 - (T/Tc)²]
  •                    Hc(T) = 0.0196[ 1 - (6/9.15)²]
  •                    Hc(T) = 0.0196x0.57  
  •                    Hc(T) = 0.011 Telsa
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