Chemistry, asked by gogineniesk, 6 months ago

The critical temperatures of O2 and N2 are 155 K and 126K respectively. Calculate the ratio of reduced
temperatures of O2 and N2 at 300 K
[ ]
b) 0.65
c) 0.812
d) 0.53
a) 0.72​

Answers

Answered by abhi178
11

Given info : The critical temperatures of O2 and N2 are 155 K and 126K respectively.

To find : Calculate the ratio of reduced

temperatures of O2 and N2 at 300 K.

Solution : reduced Temperature is given by, Tr = T/Tc

Where Tc is critical temperature of a gas at temperature T.

For O2 gas,

Reduced temperature, Tr₁ = 300K/155K

For N2 gas,

Reduced temperature, Tr₂ = 300K/126K

Now ratio of reduced temperature = Tr₁/Tr₂

= (300K/155K)/(300K/126K)

= 126/155

= 0.812

Therefore the ratio of reduced temperature of O2 and N2 is 0.812

Answered by telaprolupraneeth
0

Answer:

0.812 is the right answer..

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