The cross product of (2i-j+3k) and (i+2j-5k) vectors is
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Step-by-step explanation:
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Answer:
The cross product of 2 vectors is calculated with the determinant
∣∣ ∣ ∣∣→i→j→kdefghi∣∣ ∣ ∣∣
where →a=⟨d,e,f⟩ and →b=⟨g,h,i⟩ are the 2 vectors
Here, we have →a=⟨2,−3,4⟩ and →b=⟨1,1,−7⟩
Therefore,
∣∣ ∣ ∣∣→i→j→k2−3411−7∣∣ ∣ ∣∣
=→i∣∣∣−341−7∣∣∣−→j∣∣∣241−7∣∣∣+→k∣∣∣2−311∣∣∣
=
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