The cross- section ABCD of a swimming pool is a trapezium. it's width AB = 14 m, depth at the shallow end is 1.5 m and at the deep end is 8 m. find the area of the cross - section.
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given : ab =14cm , height = 8m, 1.5m
area of trapezium = 1/2 ( a+b) * h
here a= 14 m, b=1.5m, h= 8m
area= 1/2(14+1.5)*8
area= 62m².
Hope This Helps :)
area of trapezium = 1/2 ( a+b) * h
here a= 14 m, b=1.5m, h= 8m
area= 1/2(14+1.5)*8
area= 62m².
Hope This Helps :)
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