The cross-section ABCD of a swimming pool is
a trapezium. Its width AB = 14 m, depth at the
shallow end is 1.5 m and at the deep end is 8 m.
Find the area of the cross-section
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3
Answer:
From the figure,Area of cross section=area of rectangle ABED+area of △DEC
=14×1.5+
2
1
×6.5×14=14×
2
3
+
2
1
×6.5×14
=21+7×6.5
=21+45.5
∴Area =66.5 m
2
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Answer:
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