Question

the cross-section ABCD of a swimming pool is a trapezium. its width AB = 14m , depth at the shallow end is 1.5m and at the deep end is 8m. find the area of the cross-section​

Answer 1

Answer:

this answer is bay 16.7 that answer

Answer 2

Answer:

Width of trapezium = 14 m

Depth of shallow and deep ends are 1.5 m and 8 m

respectively.So, area of cross section

= 12(1.5+8)×14 = 9.5×7 = 66.5 m2

i hope helpful for you