the cross section of a Canal in the form of a Trapezium if the two top of the channel is 15 M wide the bottom is 8 metre and the area of cross section is 138 square find it Dept
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Answered by
9
We know,
Area of trapezium = 1/2× sum of parallel sides × height
= 1/2× (a+b) × h
Now, a = 15 m, b = 8 m and height = h and area of trapezium = 138 m2
.So, putting the respective values, we get
Area of trapezium = 1/2× (a+b) × h
⇒ 138 = 1/2×(15+8)×h
⇒ 138×2 = 23×h
⇒ 138×2/23 = h
⇒ h= 276/ 23 = 12 m
Thus, height = 12 m
Area of trapezium = 1/2× sum of parallel sides × height
= 1/2× (a+b) × h
Now, a = 15 m, b = 8 m and height = h and area of trapezium = 138 m2
.So, putting the respective values, we get
Area of trapezium = 1/2× (a+b) × h
⇒ 138 = 1/2×(15+8)×h
⇒ 138×2 = 23×h
⇒ 138×2/23 = h
⇒ h= 276/ 23 = 12 m
Thus, height = 12 m
Answered by
2
this is the wright answer
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arav40:
because 8 th is board
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