Math, asked by david734398, 1 year ago

The cross-section of a canal is in the form of a trapezium. If the top of canal is 15
wide, the bottom is 8 m and the area of cross-section is 138 m2, find its depth.​

Answers

Answered by adityamahale2003
31

Answer:

12m

Step-by-step explanation:

The cross-section of the canal forms a trapezium in which the sides of 15m and 8m are parallel.

Here,

a=15m

b=8m

h=?   (height;in this case depth)

Area of trapezium = \frac{h}{2}(a+b)

138 = \frac{h}{2}(15+8)\\\\276=23h

h= \frac{276}{23}

∴h=12m

So, the depth is 12m

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