the cross section of canal is in the form of trapezium if the top of canal is 15 M wide the bottom is 8m and the area of cross section 138 m square find its depth
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28
Answer:
12 m
Step-by-step explanation:
Area of canal = 138m².
Area of trapezium = (1/2) * (Sum of parallel sides) * (Distance between them)
⇒ 138 = (1/2) * (15 + 8) * h
⇒ 138 * 2 = 23 * h
⇒ 276 = 23 * h
⇒ h = 12 m.
The depth of the canal is 12 m
Hope it helps you.
#Bebrainly
Answered by
18
Here,
AD is the top of can = 15m
BC is the bottom of canal = 8m
We have to find the depth of the canal.
CE is the depth of canal.
Given,
Area if the canal = 138m^2
=> 1/2(a + b) × h = 138
=> 1/2(15+8)×h = 138
=> 1/2 × 23 × h = 138
=> h = 138 × 2 / 23
=> h = 6 × 2
=> h = 12m
Therefore,
AD is the top of can = 15m
BC is the bottom of canal = 8m
We have to find the depth of the canal.
CE is the depth of canal.
Given,
Area if the canal = 138m^2
=> 1/2(a + b) × h = 138
=> 1/2(15+8)×h = 138
=> 1/2 × 23 × h = 138
=> h = 138 × 2 / 23
=> h = 6 × 2
=> h = 12m
Therefore,
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Missattitude01:
Ishuu..its Priyanka
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