Question

the cross section of tunnel is in the shape of semicircle surmounted on the longer side of rectangle whose shorter side measures 6 m. if the perimeter of cross section is 66 m find height and breadth of tunnel​

Answer 1

Answer:

let 2L be the longer side of the rectangle which is the diameter of the semicircle.

So circumference of semi circle with radius L is 22/7 * L

Perimeter of the given shape = 22/7 * L + 6 + 2 L + 6

This is given as 66 m

So equating we can find the value of L = 10.5 m

Hence height of the tunnel = 10.5 + 6 = 16.5 m

Breadth of the tunnel = 21 m

Answer 2

Answer:

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Step-by-step explanation:

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