Question

The cross-sectional area of a bar magnet 10 cm long is 1.2 cm2 . If the magnetic moment of the magnet is 2.4 A.m2 , find its magnetization.​

Answer 1

Answer:

Answer refer to the attachment

Answer 2

Given:

Cross-sectional area = 1.2cm²

Length of a bar magnet = 10 cm

Magnetic moment = 2.4 Am²

To find:

Magnetisation

Solution:

Length of a bar magnet, l = 10cm = 10×0.01 m = 0.1m

Cross sectional area of a bar magnet, A = 1.2cm² = 1.2×0.01×0.01m²

                                                              A = 1.2×10⁻⁴m²

So,  Volume of a bar magnet, V = A×l

                                                 V = 1.2×10⁻⁴ × O.1

                                                 V = 1.2×10⁻⁵m³

Magnetic moment, μ = 2.4Am²

therefore, Magnetisation can be calculated as,

       ${{\text{I}}}}} = \left {\frac{{magnetic moment}}{{volume }}} \right$

       ${{\text{I}}}}} = \left {\frac{{2.4}}{{0.000012 }}} \right$

      I = 2 × 10⁵ Am⁻¹

Therefore, Magnetisation is 2 × 10⁻⁵ Am⁻¹.