Question

the cross sectional area of a bar magnet 10cm long is 1.2cm³.if the magnetic moment of the magnet is 2.4Am²,find its magnetization​

Answer 1

Answer:

Area of cross section = 4cm

2

=4×10

−4

m

2

Then,

Magnetization (M

z

)=

V

M

net

[V= l × cross-sectional area V=10×10

−2

×4×10

−4

V=4×10

−5

m

3

]

⇒M

z

=

4×10

−5

2

M

z

=5000

m

A

Answer 2

Answer:

The magnetization is : 2 x 10⁵ A/m

Explanation:

It is given to us that :

Total magnetic moment Mnet = 2.4 Am²

Cross sectional area  = 1.2 cm² = 1.2 x 10⁻⁴ m

Length, l = 10 cm = 10 x 10⁻² m

We know that, Magnetization M =$\frac{Mnet}{V}$

where Mnet = 1.4Am²

and V = length x area of cross section of the magnet

or, V = 10 x 10⁻² x  1.2 x 10⁻⁴ = 1.2 x 10⁻⁵ m²

or M = $\frac{1.4}{1.2 x 10^-5}$ = 200000 A/m = 2 x 10⁵ A/m

Magnetization :

• It is also known as magnetic polarization,

• it is also a  vector quantity.

• Magnetization also gives the measure of the density of the induced dipole moment for a particular material.

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