Question

the cross sectional area of a bar magnet 10cm long is 1.2cm³.if the magnetic moment of the magnet is 2.4Am²,find its magnetization​

Answer 1

Explanation:

Area of cross section = 4cm

2

=4×10

−4

m

2

Then,

Magnetization (M

z

)=

V

M

net

[V= l × cross-sectional area V=10×10

−2

×4×10

−4

V=4×10

−5

m

3

]

⇒M

z

=

4×10

−5

2

M

z

=5000

m

A