Question

the cross sectional area of a bar magnet 10m long is 1.2 cm ².If the magnetic moment of the magnetic is 2.4 a.m² find its magnetization.​

Answer 1

Answer:

Magnetization is 2000 A/M

Explanation:

Given,

l = 10m , cross sectional area (a) = 1.2 cm² = 1.2 × $10^{-4}$ m²

$M_{net}$ = 2.4 Am²

To find magnetization ,

$M_{z}$ = $\frac{M_net}{V}$

V = length (l) × cross sectional area (a)

⇒ 10 × 1.2 × $10^{-4}$

⇒ 1.2 × $10^{-3}$

$M_{z}$ = $\frac{2.4}{1.2 x 10^{-3} }$

$M_{z}$ = 2 x 10³ = 2000 A/M

∴ The magnetization of a bar magnet is 2000 A/M