Question

The cross sectional area of a wire is 1×10^-7 m^2 and the density of free electrons is 2×10^28 m^-3. What will be the drift velocity of the free electrons for a current of 3.2A in the wire? Ans= 1×10^-2 ms^-1​

Answer 1

CURRENT ELECTRICITY

Explanation:

★ DRIFT VELOCITY ★

★ Given ;

» Area = 1 × 10^-7 m²

» N ( No. of free electrons ) = 2 × 10^28 m³

» I ( current ) = 3.2 A

♥ By using Formula ;

$\frac {I}{A} \: = N \: × e \: × Vd </p><p>$

«★» 3.2 / 1 × 10^-7 = 2 × 10^28 × 1.6 × 10^-19 × Vd

» 3.2 × 10^7 = 3.2 × 10^9 × Vd

» 10^7 / 10^9 = Vd

«★» Vd = 1 × 10-² m/s

ANSWER :- DRIFT VELOCITY OF ELECTRONS IS 10-² m/s .