Question

The cross-sectional area of the plane shown in the figure is equal to 1 cm. 2A current flows
through a conductor. T current density at point P in the conductor will be...

Answer 1

Answer:

Where is the figure

Explanation:

Ū

Answer 2

The current density is $\dfrac{4}{\sqrt{3}}\times10^{-4}\ Am^{-2}$.

Explanation:

Given that,

Current = 2 A

Area of cross section = 1 cm²

We need to calculate the current density

Using formula of current density

$I=J\cdot A$

$J=\dfrac{I}{A\sin 60}$

Put the value into the formula

$J=\dfrac{2}{1\times\dfrac{\sqrt{3}}{2}}$

$J=\dfrac{4}{\sqrt{3}}\times10^{-4}\ Am^{-2}$

Hence, The current density is $\dfrac{4}{\sqrt{3}}\times10^{-4}\ Am^{-2}$.

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Topic : current density

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