Question

The cross-sectional area of water pipe entering the basement is 4 x 10 −4 m 2 . The pressure at this point is 3 x 10 5 N m −2 and the speed of water is 2 m s . This pipe tapers to a cross-sectional area of 2 x 10 −4 m 2 when it reaches the second floor 8 m above. Calculate the speed and pressure at the 2nd floor​

Answer 1

Answer:

use g = 10 m//s^(2). or, υ2=a1υ2a2=(4×10-4)×2.22×10-4=4.4ms-1.

Explanation:

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Answer 2

use g = 10 m//s^(2). or, u2-a1u2a2=(4x10 -4)×2.22×10-4-4.4ms-1.