Question

The CSA of frustum of a cone a slant height 10Cm and perimeter of two circular bases are 6cm and 8cm is​

Answer 1

Answer:

let r and R be the radii of circular bases of frustum,

2πr=6 and 2πR=8

r=3/π and R= 4/π Now,CSA of frustum=πl(r+R)

=π×10(3/π+4/π)

=10π×7/π

=70cm²