Question

The cube of a number is8 times the cube of another number . If the sum of the cubes of numbers is 243,the difference of the numbers is

Answer 1

OK, here we go hun :)

Let 'x' be the first number, and 'y' be the other number.

From the information provided, we have the following :

The cube of a number is 8 times the cube of another number.

x^3 = 8y^3

The sum of the cubes of the number is 243.

x^3 + y^3 = 243

We now need to solve these two equations for the two variables, 'x' and 'y':

Substitute x^3 = 8y^3 into the second equation :

8y^3 + y^3 = 243

9y^3 = 243

y^3 = 27

y = 3

To find 'x', substitute y = 3 into the first equation :

x^3 = 8 × 3^3

x^3 = 216

x = 6

So we have found x = 6 and y = 3.

The difference of these numbers is :

x - y = 6 - 3 = 3.

The difference is 3.

Hope this helps !!!!!!!!!!!!!!!!!!!!!!!!