Question

The cube of a number X is 9 times of x, then find x? (x≠0 and x≠-3)

Answer 1

Answer:

Given;

The cube of a number x is 9 times of x,

where x≠0 and x≠3.

Now,

According to question, we have;

=> x^3 = 9x

=> x^3 - 9x = 0

=> x{x^2 - 9} = 0

=> x{x^2 - 3^2} = 0

=> x(x + 3)(x - 3) = 0

=> x = 0 , 3 , -3

Here, it is given that x can't be equal to 0 and -3 , thus the appropriate value of x is 3.

Thus,

The required value of x is 3.

Answer 2

Answer:

Step-by-step explanation:

x^3=9x

x^3÷x=9

x^2=9

x=√9

x=3