The cube of a number X is 9 times of x, then find x? (x≠0 and x≠-3)
Answers
Answered by
11
Answer:
Given;
The cube of a number x is 9 times of x,
where x≠0 and x≠3.
Now,
According to question, we have;
=> x^3 = 9x
=> x^3 - 9x = 0
=> x{x^2 - 9} = 0
=> x{x^2 - 3^2} = 0
=> x(x + 3)(x - 3) = 0
=> x = 0 , 3 , -3
Here, it is given that x can't be equal to 0 and -3 , thus the appropriate value of x is 3.
Thus,
The required value of x is 3.
Answered by
18
Answer:
Step-by-step explanation:
x^3=9x
x^3÷x=9
x^2=9
x=√9
x=3
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