The cube of a positive integer
is always of the form 9m+k where
m is a whole number. What are
the possible value of k
Answers
Answered by
0
Given:
The cube of a positive integer is always of the form 9m+k where
m is a whole number
To Find:
The possible values of k.
Solution:
We can represent any number in any form as we like.
We can represent it in the form of a multiple of 3.
Let the number be P.
- P = 3q + r , q is the quotient when P is divided by 3 and r is the remainder. r ∈ { 0, 1, 2}
Now Let take Cube of P :
- P³ = (3q + r)³ = (3q)³ + r³ + 3 (3q)²r + 3(3q)r²
- P³ = 27q³ + 27q²r + 9qr² + r³
We can easily observe that 27q² + 27q²r + 9qr² = 9 x ( a number ) ,
since it is divisble by 9.
Therefore we can rewrite P as :
- P³ = 9m + r³
Comparing with the expression given in question,
- k = r³
- r³ ∈ { 0³, 1³, 2³} = {0, 1, 8}
- k can take the values 0 , 1 and 8.
The possible values of k are 0, 1 and 8.
Answered by
0
Answer:The cube of a positive integer
is always of the form 9m+k where
m is a whole number. What are
the possible value of k
Step-by-step explanation: hdfn
5+602+85
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