The cube of a positive integer is divided by 9 what can be the possible remainder
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Our question is: The cube of a positive integer is divided by 9 what can be the possible remainder
We need to consider that cube of 2 is equal to 8, then it is not divisible by 9. Now if we compute the cube of 3 we get 27, which is divisible by 9, and if we compute 27 / 9 = 0 * 9 + 3.
Hence we can conclude that the remainder is equal to three.
Therefore the remainder is 3.
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