Question

The cube of the difference of a number and 4.

Answer 1

Answer:

data in sufficient.

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Answer 2

The cube of difference of a number and 4 is $x^{3} - 12x^{2} + 48x - 64$.

Given,

The number that is to be subtracted= 4

To Find,

The cube of the difference of a number and 4.

Solution,

Let us take the number as 'x'.

Now, the difference between both the numbers are $= (x -4)$

Cube of this difference $= (x-4)^{3}$

Applying the formula

$(a - b)^{3} = a^{3} - 3a^{2} b + 3ab^{2} - b^{3}$

We get  $(x - 4)^{3}$ $= x^{3} + 3x^{2} .(-4) + 3x(4)^{2} + (-4)^{3}$

                         $= x^{3} - 12x^{2} + 48x - 64$

Hence, the answer is $x^{3} - 12x^{2} + 48x - 64$

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