the cube of the difference of two numbers 'a' and 'b' is 27 and the product of these numbers is 40 find the value of (2a2+2ab+2b2) given a>b
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The Theorem of Pythagoras
(a + b)2 = a2 + 2ab + b2 (recall that 2ab means 2 times a times b). For example 152 = (10 + 5)2 ...
(a - b) 2 = a2 - 2ab + b2 For example: 52 = (10 - 5)2 = 102 - (2)(10)(5) + 52 ...
(a + b) 2 = (4)(1/2)(a)(b) + c2 ...
a2 + 2ab + b2 = 2ab + c2 ...
a2 + b2 = c2
Step-by-step explanation:
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