Question

(The cube root of -5/6) divided by (cube root of -5/8)​

Answer 1

Answer:

cube root of a number x is a number y such that y3 = x. All nonzero real numbers, have exactly one real cube root and a pair of complex conjugate cube roots, and all nonzero complex numbers have three distinct complex cube roots. For example, the real cube root of 8, denoted {\displaystyle {\sqrt[{3}]{8}}}{\displaystyle {\sqrt[{3}]{8}}}, is 2, because 23 = 8, while the other cube roots of 8 are {\displaystyle -1+i{\sqrt {3}}}{\displaystyle -1+i{\sqrt {3}}} and {\displaystyle -1-i{\sqrt {3}}}{\displaystyle -1-i{\sqrt {3}}}. The three cube roots of −27i are

Answer 2

Answer:

I didn't understand

Step-by-step explanation:

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