Question

The cubic polynomial p(x)=x^3-x has _____ number of zeros.
(1-mark)​..

Answer 1

Answer:

Given, x³ - x = x( x² - 1)

[because a²-b²=(a-b)(a+b)]

= x [ (x-1)(x+1) ]

= x(x-1)(x+1)

So, given polynomial has three zeroes i.e x=0,1 & -1