Question

The cubic polynomial with sum; sum of the product of its zeroes taken two at a time and the product of the zeroes as 2 , -7 , -14 respectively is

Answer 1

Step-by-step explanation:

${ax}^{3} + {bx}^{2} + cx + d \\ a = 2 \: \\ b = - 7 \\ c = - 11 \\ \alpha + \beta + \gamma = \frac{7}{2} \\ \alpha \beta + \beta \gamma + \gamma \alpha = \frac{ - 11}{2} \\ \alpha \beta \gamma = \frac{11}{2} \\ {2x}^{3} { - 7x}^{2} - 11x + y = 0$

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