Question

The cubic unit cell structure of a compound containing cation M and anion X is shown below. When compared to the anion, the cation has a smaller ionic radius. Choose the correct statement(s).

Answer 1

solution : number of cation M in the cell = 2 × 1/2 = 2 [ as cations are placed on the faces of cube ]

number of anion in the cell = 4 × 1/4 = 1 [ as anions are placed midpoint of edge corner of the cube ]

so, empirical formula of compound is M₁X₁ = MX

option (A) is correct choice.

coordination number of an atom is number of atom it is touching.

here coordinate number of M and X are same and that is 8. so option (B) is incorrect.

bond length of M - X bond = AB = √3 × a/2

here a is edge length of cubic unit cell

so, AB/a = √3/2 = 1.732/2 = 0.866 , so option (C) is correct choice.

[ AB = (diagonal of face/2)² + (edge length/2)² ]

we know, ratio of cation and anion is 0.732 to 1.00 if coordination number is 8.

So option (D) is incorrect..

Therefore options (A) and (C) are correct choices.

Answer 2

Answer:C

Explanation:g