Question

The cuboidal room of Harsh has volume = x3 – Px + 6 and length of the room is given by x – 1.What is the value of P? Hint: Length will be a factor of the volume. Use remainder theorem(A) We can't find the value of P from given information(B) 7(C) 5(D) -7plz me guys!!!​

Answer 1

Answer:

Here ya go!

Step-by-step explanation:

p(x)= x³-Px+6

x=1

p(1)= (1)³-P(1)+6

    = 1-P+6

    = 5-P

P=5

(C) 5

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Answer 2

Answer:

Hence the correct answer is option(b) 7

Step-by-step explanation:

Given,

The volume of room = x³ – Px + 6

Length of the room = (x-1)

To find,

The value of 'p'

Recall the formula

The volume of a cuboid  = length × breadth × height

Factor theorem:

If p(x) is a polynomial of degree n ≥ 1 and the linear polynomial (x-a) is a factor of p(x). Then p(a) = 0

Solution:

Since volume of the cuboid is length × breadth × height, we have

length is a factor of the volume of the cuboid

Here Volume of the cuboid is x³ – Px + 6 and length is (x-1), we have

(x-1) is factor of x³ – Px + 6

Let p(x) = x³ – Px + 6,

Since (x-1) is a factor of p(x), by factor theorem we have

p(1) = 0

1³ - P ×1 +6 = 0

1 - P +6 = 0

P = 6+1 = 7

∴ The value of P = 7

Hence the correct answer is option(b) 7

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