Question

the Curcumference of the base of a Cylinder
vessel is 132 cm and its height is 25 cm
How many litres of water can it hold​

Answer 1

Given:-

• Circumference = 132 cm
• Height (h) = 25 cm

Here, let the radius of circle be r cm.

As we know that,

Circumference of circle = 2πr

132 = 2 × 22 / 7 × r

132 × 7 / 44 = r

r = 21 cm

By using another formula for volume,

Volume of cylinder = πr²h

= 22/7 × 21 × 21 × 25

= 34650 cm³

Now,

1 cm³ = 0.001 litres

34650 cm³ = 34.65 litres

Therefore, 34.65 litres of water it can hold.

Answer 2

Answer:

Given :-

• Circumference = 132 cm
• Height = 25 cm

To Find :-

Water it can hold

Solution :-

Firstly let's find Radius of cylinder

$\large \sf \: Circumference = 2\pi r$

$\large \sf \: 132 = 2 \times \dfrac{22}{7} \times r$

$\large \sf \: 132 = \dfrac{44}{7} \times r$

$\large \sf \: r \: = 132 \times \dfrac{7}{44} \bigg \lgroup \: 132 \: to \: RHS \: and \: r \: to \: LHS \bigg \rgroup$

$\large \sf \: r \: = 21 \: m$

Now,

Finding Volume

$\bigg \lgroup \large \sf \: Volume \: = \pi {r}^{2} h \bigg \rgroup$

$\large \sf \: Volume \: = \dfrac{22}{7} \times {21}^{2} \times 25$

$\large \sf \: Volume \: = \dfrac{22}{ \cancel7} \times \cancel{21 }\times 21 \times 25$

$\large \sf \: Volume \: = 22 \times 3 \times 21 \times 25$

$\large \sf \: Volume \: = 34650 \: {cm}^{3}$

Now,

Converting units

1000 cm = 1 l

34650 cm = 34.650 l