The current density in a cylindrical wire of radius
2-0 mm is uniform across a cross-section of wire
and is equal to 2-0 x 10 Am - 2. What is
(a) current in the wire?
(b) current through cross-section of wire
between radial distance 1.0 mm to 2.0mm?
Answers
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Answer:
A solid cylindrical conductor of radius
′
R
′
has a uniform current density. The magnetic field
′
H
′
insider the conductor at a distance
′
r
′
from the axis of the conductor is:
HARD
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ANSWER
Magnetic field at a distance r inside a conductor of radius R is given by ampere’s circuital law
B×2πr=μ
0
Jπr
2
B=
2
μ
0
Jr
B=
2πR
2
μ
0
rI
Thus magnetic field inside a conductor is given by
B=
2πR
2
μ
0
rI
Magnetic field strength
H=
μ
0
B
H=
2πR
2
Ir
Explanation:
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