Physics, asked by keerthi0646, 1 year ago

The current enters to the positive terminal of a device is i(t)=20e−4t amps, and the voltage across the device is v(t)=3di(t)dt volt. The amount of the charge delivered (in C) to the device between t=0 and t=2 seconds.

Answers

Answered by saratheharshita

Since i=dq/dt
dq=idt...we integrate both sides as we want the amount of charge delivered in time interval 0-2 seconds.

Attachments:

hirthickvelu: he current enters to the positive terminal of a device is i(t)=20e−4t amps, and the voltage across the device is v(t)=3di(t)dt volt. The amount of the charge delivered (in C) to the device between t=0 and t=2 seconds.

4.90−5.0

9.90−10.0

79−80

39−40

hirthickvelu: the current enters to the positive terminal of a device is i(t)=20e−4t amps, and the voltage across the device is v(t)=3di(t)dt volt. The amount of the charge delivered (in C) to the device between t=0 and t=2 seconds.

4.90−5.0

9.90−10.0

79−80

39−40

Read more on Brainly.in - https://brainly.in/question/5186966#readmore

hirthickvelu: Which answer is correct in above

Previous Question

Next Question