the current enters to the positive terminal of a device is i(t)=20eâ’4t amps and the voltage across the device is v(t)=3di(t)dt volt. the amount of the charge delivered (in c) to the device between t=0 and t=2 seconds.
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The energy absorbed can be found by:
W is the energy absorbed, v will be the voltage, I current and t is the time,
W = integration from t1 to t2 V * I dt
Putting the value in the equation
Integration from 0 to 2 (3di(t) * 20 ea^4t dt
You need to solve the integration and put the value in it.
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