Question

the current flowing in a wire is one ampere if the charge of an electron is 1.6 into 10 power minus 19 coulomb then the number of electrons flowing through the wire per second is​

Answer 1

Answer:

6.25 × 10¹⁸

Explanation:

charge on an electron = 1.6 × 10⁻¹⁹

therefore , no. of electrons

= total charge / charge on an electron

= 1  / ( 1.6 × 10⁻¹⁹)

= 6.25 × 10¹⁸

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Answer 2

There are $6.25\times 10^{18}\ electrons$ are flowing through the wire per second.

Explanation:

Given that,

Current flowing in a wire, I = 1 A

Charge on an electron, $q=1.6\times 10^{-19}\ C$

Electric current is defined as the electric charge per unit time. We need to find the number of electrons flowing through the wire per second. It is given by :

$I=\dfrac{q}{t}$

Since, q = ne

$I=\dfrac{ne}{t}$

$n=\dfrac{It}{e}$

$n=\dfrac{1\times 1}{1.6\times 10^{-19}}$

$n=6.25\times 10^{18}\ electrons$

So, there are $6.25\times 10^{18}\ electrons$ are flowing through the wire per second. Hence, this is the required solution.

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